MATH SOLVE

3 months ago

Q:
# A survey is taken among customers of a fast-food restaurant to determine preference for hamburger or chicken. Of 200 respondents selected, 75 were children and 125 were adults. 120 preferred hamburger and 80 preferred chickens. 55 of the children preferred hamburger and 20 preferred chickens. Set up a 2x2 contingency table using this information and answer the following questions:FoodAge Hamburger Chicken TotalChild 55 20 75Adult 65 60 125Total 120 80 200a) What is the probability that a randomly selected individual is an adult?b) What is the probability that a randomly selected individual is a child and prefers chicken?c) Given the person is a child, what is the probability that this child prefers a hamburger?d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?

Accepted Solution

A:

Answer: Hamburger ChickenAdults 65 60 125children 55 20 75 120 80 200a)What is the probability that a randomly selected individual is an adult?Total no. of adults = 125 Total no. of people 200 The probability that a randomly selected individual is an adult = [tex]\frac{125}{200}=0.625[/tex]b) What is the probability that a randomly selected individual is a child and prefers chicken?No. of child prefers chicken = 20 The probability that a randomly selected individual is a child and prefers chicken= [tex]\frac{20}{200}=0.1[/tex]c)Given the person is a child, what is the probability that this child prefers a hamburger?No. of children prefer hamburger = 55No. of child = 75The probability that this child prefers a hamburger= [tex]\frac{35}{75}=0.46[/tex]d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?No. of adults prefer chicken = 60No. of total people like chicken = 80A person has ordered chicken, the probability that this individual is an adult= [tex]\frac{60}{80}=0.75[/tex]